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 Then by the Fundamental Theorem of Calculus F ′ (x) = f(x) Changing variables u = x t we get g(x) = ∫b af(x t)dt = ∫b x a xf(u)du = F(b x) − F(x a) Differentiating the above we finally have g ′ (x) = F ′ (b x) − F ′ (x a) = f(b x) − f(x a) Share answered Jun 1 ' at 2225 Tony419Inverse Functions Inverse functions are functions that undo one another In other words, if f1 (x) is the inverse of f(x), then f(f1 (x)) = f1 (f(x)) = xWe can use this definition to solveX l ð ¦ µ Ä ¨ è C ib j Í6 D5 Ì w ¦ ² ß v Æ ¯ l Ì ² ß Ì Ý è C ì ð f B X v C ã Å s ¤ O t B b N æ Ê Ì á Å é B ib j ² ß Ì \ ¦ 2 ƒVƒ‡[ƒgƒwƒA ƒƒbƒNƒX ‚¨‚·‚·‚ß ƒŒƒfƒB[ƒX

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